4 coal pyramid. Geometric figures

23.09.2019

Definition

Pyramid is a polyhedron composed of a polygon \(A_1A_2...A_n\) and \(n\) triangles with a common vertex \(P\) (not lying in the plane of the polygon) and opposite sides coinciding with the sides of the polygon.
Designation: \(PA_1A_2...A_n\) .
Example: pentagonal pyramid \(PA_1A_2A_3A_4A_5\) .

Triangles \(PA_1A_2, \ PA_2A_3\) etc. called side faces pyramids, segments \(PA_1, PA_2\), etc. - side ribs, polygon \(A_1A_2A_3A_4A_5\) – basis, point \(P\) – summit.

Height Pyramids are a perpendicular dropped from the top of the pyramid to the plane of the base.

A pyramid with a triangle at its base is called tetrahedron.

The pyramid is called correct, if its base is a regular polygon and one of the following conditions is met:

\((a)\) side edges of the pyramid are equal;

\((b)\) the height of the pyramid passes through the center of the circumscribed circle near the base;

\((c)\) side ribs are inclined to the base plane at the same angle.

\((d)\) side faces are inclined to the base plane at the same angle.

regular tetrahedron is a triangular pyramid, all the faces of which are equal equilateral triangles.

Theorem

The conditions \((a), (b), (c), (d)\) are equivalent.

Proof

Draw the height of the pyramid \(PH\) . Let \(\alpha\) be the plane of the base of the pyramid.


1) Let us prove that \((a)\) implies \((b)\) . Let \(PA_1=PA_2=PA_3=...=PA_n\) .

Because \(PH\perp \alpha\) , then \(PH\) is perpendicular to any line lying in this plane, so the triangles are right-angled. So these triangles are equal in common leg \(PH\) and hypotenuse \(PA_1=PA_2=PA_3=...=PA_n\) . So \(A_1H=A_2H=...=A_nH\) . This means that the points \(A_1, A_2, ..., A_n\) are at the same distance from the point \(H\) , therefore, they lie on the same circle with radius \(A_1H\) . This circle, by definition, is circumscribed about the polygon \(A_1A_2...A_n\) .

2) Let us prove that \((b)\) implies \((c)\) .

\(PA_1H, PA_2H, PA_3H,..., PA_nH\) rectangular and equal in two legs. Hence, their angles are also equal, therefore, \(\angle PA_1H=\angle PA_2H=...=\angle PA_nH\).

3) Let us prove that \((c)\) implies \((a)\) .

Similar to the first point, triangles \(PA_1H, PA_2H, PA_3H,..., PA_nH\) rectangular and along the leg and acute angle. This means that their hypotenuses are also equal, that is, \(PA_1=PA_2=PA_3=...=PA_n\) .

4) Let us prove that \((b)\) implies \((d)\) .

Because in a regular polygon, the centers of the circumscribed and inscribed circles coincide (generally speaking, this point is called the center of a regular polygon), then \(H\) is the center of the inscribed circle. Let's draw perpendiculars from the point \(H\) to the sides of the base: \(HK_1, HK_2\), etc. These are the radii of the inscribed circle (by definition). Then, according to the TTP, (\(PH\) is a perpendicular to the plane, \(HK_1, HK_2\), etc. are projections perpendicular to the sides) oblique \(PK_1, PK_2\), etc. perpendicular to the sides \(A_1A_2, A_2A_3\), etc. respectively. So, by definition \(\angle PK_1H, \angle PK_2H\) equal to the angles between the side faces and the base. Because triangles \(PK_1H, PK_2H, ...\) are equal (as right-angled on two legs), then the angles \(\angle PK_1H, \angle PK_2H, ...\) are equal.

5) Let us prove that \((d)\) implies \((b)\) .

Similarly to the fourth point, the triangles \(PK_1H, PK_2H, ...\) are equal (as rectangular along the leg and acute angle), which means that the segments \(HK_1=HK_2=...=HK_n\) are equal. Hence, by definition, \(H\) is the center of a circle inscribed in the base. But since for regular polygons, the centers of the inscribed and circumscribed circles coincide, then \(H\) is the center of the circumscribed circle. Chtd.

Consequence

The side faces of a regular pyramid are equal isosceles triangles.

Definition

The height of the side face of a regular pyramid, drawn from its top, is called apothema.
The apothems of all lateral faces of a regular pyramid are equal to each other and are also medians and bisectors.

Important Notes

1. The height of a regular triangular pyramid falls to the intersection point of the heights (or bisectors, or medians) of the base (the base is a regular triangle).

2. The height of a regular quadrangular pyramid falls to the point of intersection of the diagonals of the base (the base is a square).

3. The height of a regular hexagonal pyramid falls to the point of intersection of the diagonals of the base (the base is a regular hexagon).

4. The height of the pyramid is perpendicular to any straight line lying at the base.

Definition

The pyramid is called rectangular if one of its lateral edges is perpendicular to the plane of the base.


Important Notes

1. For a rectangular pyramid, the edge perpendicular to the base is the height of the pyramid. That is, \(SR\) is the height.

2. Because \(SR\) perpendicular to any line from the base, then \(\triangle SRM, \triangle SRP\) are right triangles.

3. Triangles \(\triangle SRN, \triangle SRK\) are also rectangular.
That is, any triangle formed by this edge and the diagonal coming out of the vertex of this edge, which lies at the base, will be right-angled.

\[(\Large(\text(Volume and surface area of ​​the pyramid)))\]

Theorem

The volume of a pyramid is equal to one third of the product of the area of ​​the base and the height of the pyramid: \

Consequences

Let \(a\) be the side of the base, \(h\) be the height of the pyramid.

1. The volume of a regular triangular pyramid is \(V_(\text(right triangle pyr.))=\dfrac(\sqrt3)(12)a^2h\),

2. The volume of a regular quadrangular pyramid is \(V_(\text(right.four.pyre.))=\dfrac13a^2h\).

3. The volume of a regular hexagonal pyramid is \(V_(\text(right.hex.pyr.))=\dfrac(\sqrt3)(2)a^2h\).

4. The volume of a regular tetrahedron is \(V_(\text(right tetra.))=\dfrac(\sqrt3)(12)a^3\).

Theorem

The area of ​​the lateral surface of a regular pyramid is equal to half the product of the perimeter of the base and the apothem.

\[(\Large(\text(Truncated pyramid)))\]

Definition

Consider an arbitrary pyramid \(PA_1A_2A_3...A_n\) . Let us draw a plane parallel to the base of the pyramid through a certain point lying on the side edge of the pyramid. This plane will divide the pyramid into two polyhedra, one of which is a pyramid (\(PB_1B_2...B_n\) ), and the other is called truncated pyramid(\(A_1A_2...A_nB_1B_2...B_n\) ).


The truncated pyramid has two bases - polygons \(A_1A_2...A_n\) and \(B_1B_2...B_n\) , which are similar to each other.

The height of a truncated pyramid is a perpendicular drawn from some point of the upper base to the plane of the lower base.

Important Notes

1. All side faces of a truncated pyramid are trapezoids.

2. The segment connecting the centers of the bases of a regular truncated pyramid (that is, a pyramid obtained by a section of a regular pyramid) is a height.

This video tutorial will help users to get an idea about Pyramid theme. Correct pyramid. In this lesson, we will get acquainted with the concept of a pyramid, give it a definition. Consider what a regular pyramid is and what properties it has. Then we prove the theorem on the lateral surface of a regular pyramid.

In this lesson, we will get acquainted with the concept of a pyramid, give it a definition.

Consider a polygon A 1 A 2...A n, which lies in the plane α, and a point P, which does not lie in the plane α (Fig. 1). Let's connect the dot P with peaks A 1, A 2, A 3, … A n. Get n triangles: A 1 A 2 R, A 2 A 3 R and so on.

Definition. Polyhedron RA 1 A 2 ... A n, made up of n-gon A 1 A 2...A n And n triangles RA 1 A 2, RA 2 A 3RA n A n-1 , called n- coal pyramid. Rice. 1.

Rice. 1

Consider a quadrangular pyramid PABCD(Fig. 2).

R- the top of the pyramid.

ABCD- the base of the pyramid.

RA- side rib.

AB- base edge.

From a point R drop the perpendicular RN on the ground plane ABCD. The perpendicular drawn is the height of the pyramid.

Rice. 2

The total surface of the pyramid consists of the lateral surface, that is, the area of ​​all lateral faces, and the base area:

S full \u003d S side + S main

A pyramid is called correct if:

  • its base is a regular polygon;
  • the segment connecting the top of the pyramid with the center of the base is its height.

Explanation on the example of a regular quadrangular pyramid

Consider a regular quadrangular pyramid PABCD(Fig. 3).

R- the top of the pyramid. base of the pyramid ABCD- a regular quadrilateral, that is, a square. Dot ABOUT, the intersection point of the diagonals, is the center of the square. Means, RO is the height of the pyramid.

Rice. 3

Explanation: in the right n-gon, the center of the inscribed circle and the center of the circumscribed circle coincide. This center is called the center of the polygon. Sometimes they say that the top is projected into the center.

The height of the side face of a regular pyramid, drawn from its top, is called apothema and denoted h a.

1. all side edges of a regular pyramid are equal;

2. side faces are equal isosceles triangles.

Let us prove these properties using the example of a regular quadrangular pyramid.

Given: RABCD- regular quadrangular pyramid,

ABCD- square,

RO is the height of the pyramid.

Prove:

1. RA = PB = PC = PD

2.∆ATP = ∆BCP = ∆CDP = ∆DAP See Fig. 4.

Rice. 4

Proof.

RO is the height of the pyramid. That is, straight RO perpendicular to the plane ABC, and hence direct AO, VO, SO And DO lying in it. So the triangles ROA, ROV, ROS, ROD- rectangular.

Consider a square ABCD. It follows from the properties of a square that AO = BO = CO = DO.

Then the right triangles ROA, ROV, ROS, ROD leg RO- general and legs AO, VO, SO And DO equal, so these triangles are equal in two legs. From the equality of triangles follows the equality of segments, RA = PB = PC = PD. Point 1 is proven.

Segments AB And sun are equal because they are sides of the same square, RA = RV = PC. So the triangles AVR And VCR - isosceles and equal on three sides.

Similarly, we get that the triangles ABP, BCP, CDP, DAP are isosceles and equal, which was required to prove in item 2.

The area of ​​the lateral surface of a regular pyramid is equal to half the product of the perimeter of the base and the apothem:

For the proof, we choose a regular triangular pyramid.

Given: RAVS is a regular triangular pyramid.

AB = BC = AC.

RO- height.

Prove: . See Fig. 5.

Rice. 5

Proof.

RAVS is a regular triangular pyramid. That is AB= AC = BC. Let ABOUT- the center of the triangle ABC, Then RO is the height of the pyramid. The base of the pyramid is an equilateral triangle. ABC. notice, that .

triangles RAV, RVS, RSA- equal isosceles triangles (by property). A triangular pyramid has three side faces: RAV, RVS, RSA. So, the area of ​​the lateral surface of the pyramid is:

S side = 3S RAB

The theorem has been proven.

The radius of a circle inscribed in the base of a regular quadrangular pyramid is 3 m, the height of the pyramid is 4 m. Find the area of ​​the lateral surface of the pyramid.

Given: regular quadrangular pyramid ABCD,

ABCD- square,

r= 3 m,

RO- the height of the pyramid,

RO= 4 m.

Find: S side. See Fig. 6.

Rice. 6

Solution.

According to the proven theorem, .

Find the side of the base first AB. We know that the radius of a circle inscribed in the base of a regular quadrangular pyramid is 3 m.

Then, m.

Find the perimeter of the square ABCD with a side of 6 m:

Consider a triangle BCD. Let M- middle side DC. Because ABOUT- middle BD, That (m).

Triangle DPC- isosceles. M- middle DC. That is, RM- the median, and hence the height in the triangle DPC. Then RM- apothem of the pyramid.

RO is the height of the pyramid. Then, straight RO perpendicular to the plane ABC, and hence the direct OM lying in it. Let's find an apothem RM from a right triangle ROM.

Now we can find the side surface of the pyramid:

Answer: 60 m2.

The radius of a circle circumscribed near the base of a regular triangular pyramid is m. The lateral surface area is 18 m 2. Find the length of the apothem.

Given: ABCP- regular triangular pyramid,

AB = BC = SA,

R= m,

S side = 18 m 2.

Find: . See Fig. 7.

Rice. 7

Solution.

In a right triangle ABC given the radius of the circumscribed circle. Let's find a side AB this triangle using the sine theorem.

Knowing the side of a regular triangle (m), we find its perimeter.

According to the theorem on the area of ​​the lateral surface of a regular pyramid, where h a- apothem of the pyramid. Then:

Answer: 4 m.

So, we examined what a pyramid is, what a regular pyramid is, we proved the theorem on the lateral surface of a regular pyramid. In the next lesson, we will get acquainted with the truncated pyramid.

Bibliography

  1. Geometry. Grade 10-11: a textbook for students of educational institutions (basic and profile levels) / I. M. Smirnova, V. A. Smirnov. - 5th ed., Rev. and additional - M.: Mnemosyne, 2008. - 288 p.: ill.
  2. Geometry. Grade 10-11: A textbook for general educational institutions / Sharygin I. F. - M .: Bustard, 1999. - 208 p.: ill.
  3. Geometry. Grade 10: Textbook for general educational institutions with in-depth and profile study of mathematics / E. V. Potoskuev, L. I. Zvalich. - 6th ed., stereotype. - M.: Bustard, 008. - 233 p.: ill.
  1. Internet portal "Yaklass" ()
  2. Internet portal "Festival of Pedagogical Ideas "First of September" ()
  3. Internet portal "Slideshare.net" ()

Homework

  1. Can a regular polygon be the base of an irregular pyramid?
  2. Prove that non-intersecting edges of a regular pyramid are perpendicular.
  3. Find the value of the dihedral angle at the side of the base of a regular quadrangular pyramid, if the apothem of the pyramid is equal to the side of its base.
  4. RAVS is a regular triangular pyramid. Construct the linear angle of the dihedral angle at the base of the pyramid.

Introduction

When we began to study stereometric figures, we touched on the topic "Pyramid". We liked this theme because the pyramid is very often used in architecture. And since our future profession as an architect, inspired by this figure, we think that she will be able to push us to great projects.

The strength of architectural structures, their most important quality. Associating strength, firstly, with the materials from which they are created, and, secondly, with the features of design solutions, it turns out that the strength of a structure is directly related to the geometric shape that is basic for it.

In other words, we are talking about the geometric figure that can be considered as a model of the corresponding architectural form. It turns out that the geometric shape also determines the strength of the architectural structure.

The Egyptian pyramids have long been considered the most durable architectural structure. As you know, they have the shape of regular quadrangular pyramids.

It is this geometric shape that provides the greatest stability due to the large base area. On the other hand, the shape of the pyramid ensures that the mass decreases as the height above the ground increases. It is these two properties that make the pyramid stable, and therefore strong in the conditions of gravity.



Objective of the project: learn something new about the pyramids, deepen knowledge and find practical applications.

To achieve this goal, it was necessary to solve the following tasks:

Learn historical information about the pyramid

Consider the pyramid as a geometric figure

Find application in life and architecture

Find similarities and differences between pyramids located in different parts of the world


Theoretical part

Historical information

The beginning of the geometry of the pyramid was laid in ancient Egypt and Babylon, but it was actively developed in ancient Greece. The first to establish what the volume of the pyramid is equal to was Democritus, and Eudoxus of Cnidus proved it. The ancient Greek mathematician Euclid systematized knowledge about the pyramid in the XII volume of his "Beginnings", and also brought out the first definition of the pyramid: a bodily figure bounded by planes that converge from one plane at one point.

The tombs of the Egyptian pharaohs. The largest of them - the pyramids of Cheops, Khafre and Mikerin in El Giza in ancient times were considered one of the Seven Wonders of the World. The erection of the pyramid, in which the Greeks and Romans already saw a monument to the unprecedented pride of kings and cruelty, which doomed the entire people of Egypt to senseless construction, was the most important cult act and was supposed to express, apparently, the mystical identity of the country and its ruler. The population of the country worked on the construction of the tomb in the part of the year free from agricultural work. A number of texts testify to the attention and care that the kings themselves (albeit of a later time) paid to the construction of their tomb and its builders. It is also known about the special cult honors that turned out to be the pyramid itself.


Basic concepts

Pyramid A polyhedron is called, the base of which is a polygon, and the remaining faces are triangles having a common vertex.

Apothem- the height of the side face of a regular pyramid, drawn from its top;

Side faces- triangles converging at the top;

Side ribs- common sides of the side faces;

top of the pyramid- a point connecting the side edges and not lying in the plane of the base;

Height- a segment of a perpendicular drawn through the top of the pyramid to the plane of its base (the ends of this segment are the top of the pyramid and the base of the perpendicular);

Diagonal section of a pyramid- section of the pyramid passing through the top and the diagonal of the base;

Base- a polygon that does not belong to the top of the pyramid.

The main properties of the correct pyramid

Side edges, side faces and apothems are equal, respectively.

The dihedral angles at the base are equal.

The dihedral angles at the side edges are equal.

Each height point is equidistant from all base vertices.

Each height point is equidistant from all side faces.


Basic pyramid formulas

The area of ​​the lateral and full surface of the pyramid.

The area of ​​the lateral surface of the pyramid (full and truncated) is the sum of the areas of all its lateral faces, the total surface area is the sum of the areas of all its faces.

Theorem: The area of ​​the lateral surface of a regular pyramid is equal to half the product of the perimeter of the base and the apothem of the pyramid.

p- perimeter of the base;

h- apothem.

The area of ​​the lateral and full surfaces of a truncated pyramid.

p1, p 2 - base perimeters;

h- apothem.

R- total surface area of ​​a regular truncated pyramid;

S side- area of ​​the lateral surface of a regular truncated pyramid;

S1 + S2- base area

Pyramid Volume

Form The volume scale is used for pyramids of any kind.

H is the height of the pyramid.


Angles of the pyramid

The angles that are formed by the side face and the base of the pyramid are called dihedral angles at the base of the pyramid.

A dihedral angle is formed by two perpendiculars.

To determine this angle, you often need to use the three perpendiculars theorem.

The angles that are formed by a side edge and its projection onto the plane of the base are called angles between the lateral edge and the plane of the base.

The angle formed by two side faces is called dihedral angle at the lateral edge of the pyramid.

The angle, which is formed by two side edges of one face of the pyramid, is called corner at the top of the pyramid.


Sections of the pyramid

The surface of a pyramid is the surface of a polyhedron. Each of its faces is a plane, so the section of the pyramid given by the secant plane is a broken line consisting of separate straight lines.

Diagonal section

The section of a pyramid by a plane passing through two lateral edges that do not lie on the same face is called diagonal section pyramids.

Parallel sections

Theorem:

If the pyramid is crossed by a plane parallel to the base, then the side edges and heights of the pyramid are divided by this plane into proportional parts;

The section of this plane is a polygon similar to the base;

The areas of the section and the base are related to each other as the squares of their distances from the top.

Types of pyramid

Correct pyramid- a pyramid, the base of which is a regular polygon, and the top of the pyramid is projected into the center of the base.

At the correct pyramid:

1. side ribs are equal

2. side faces are equal

3. apothems are equal

4. dihedral angles at the base are equal

5. dihedral angles at side edges are equal

6. each height point is equidistant from all base vertices

7. each height point is equidistant from all side faces

Truncated pyramid- the part of the pyramid enclosed between its base and a cutting plane parallel to the base.

The base and corresponding section of a truncated pyramid are called bases of a truncated pyramid.

A perpendicular drawn from any point of one base to the plane of another is called the height of the truncated pyramid.


Tasks

No. 1. In a regular quadrangular pyramid, point O is the center of the base, SO=8 cm, BD=30 cm. Find the side edge SA.


Problem solving

No. 1. In a regular pyramid, all faces and edges are equal.

Let's consider OSB: OSB-rectangular rectangle, because.

SB 2 \u003d SO 2 + OB 2

SB2=64+225=289

Pyramid in architecture

Pyramid - a monumental structure in the form of an ordinary regular geometric pyramid, in which the sides converge at one point. According to the functional purpose, the pyramids in ancient times were a place of burial or worship. The base of a pyramid can be triangular, quadrangular, or polygonal with an arbitrary number of vertices, but the most common version is the quadrangular base.

A considerable number of pyramids are known, built by different cultures of the Ancient World, mainly as temples or monuments. The largest pyramids are the Egyptian pyramids.

All over the Earth you can see architectural structures in the form of pyramids. Pyramid buildings are reminiscent of ancient times and look very beautiful.

The Egyptian pyramids are the greatest architectural monuments of Ancient Egypt, among which one of the "Seven Wonders of the World" is the pyramid of Cheops. From the foot to the top, it reaches 137.3 m, and before it lost the top, its height was 146.7 m.

The building of the radio station in the capital of Slovakia, resembling an inverted pyramid, was built in 1983. In addition to offices and service premises, there is a fairly spacious concert hall inside the volume, which has one of the largest organs in Slovakia.

The Louvre, which "is as silent and majestic as a pyramid" has undergone many changes over the centuries before becoming the greatest museum in the world. It was born as a fortress, erected by Philip Augustus in 1190, which soon turned into a royal residence. In 1793 the palace became a museum. Collections are enriched through bequests or purchases.

When solving problem C2 using the coordinate method, many students face the same problem. They can't calculate point coordinates included in the scalar product formula. The greatest difficulties are pyramids. And if the base points are considered more or less normal, then the tops are a real hell.

Today we will deal with a regular quadrangular pyramid. There is also a triangular pyramid (aka - tetrahedron). This is a more complex design, so a separate lesson will be devoted to it.

Let's start with the definition:

A regular pyramid is one in which:

  1. The base is a regular polygon: triangle, square, etc.;
  2. The height drawn to the base passes through its center.

In particular, the base of a quadrangular pyramid is square. Just like Cheops, only a little smaller.

Below are the calculations for a pyramid with all edges equal to 1. If this is not the case in your problem, the calculations do not change - just the numbers will be different.

Vertices of a quadrangular pyramid

So, let a regular quadrangular pyramid SABCD be given, where S is the top, the base of ABCD is a square. All edges are equal to 1. It is required to enter a coordinate system and find the coordinates of all points. We have:

We introduce a coordinate system with the origin at point A:

  1. The axis OX is directed parallel to the edge AB ;
  2. Axis OY - parallel to AD . Since ABCD is a square, AB ⊥ AD ;
  3. Finally, the OZ axis is directed upward, perpendicular to the plane ABCD.

Now we consider the coordinates. Additional construction: SH - height drawn to the base. For convenience, we will take out the base of the pyramid in a separate figure. Since the points A , B , C and D lie in the OXY plane, their coordinate is z = 0. We have:

  1. A = (0; 0; 0) - coincides with the origin;
  2. B = (1; 0; 0) - step by 1 along the OX axis from the origin;
  3. C = (1; 1; 0) - step by 1 along the OX axis and by 1 along the OY axis;
  4. D = (0; 1; 0) - step only along the OY axis.
  5. H \u003d (0.5; 0.5; 0) - the center of the square, the middle of the segment AC.

It remains to find the coordinates of the point S. Note that the x and y coordinates of the points S and H are the same because they lie on a straight line parallel to the OZ axis. It remains to find the z coordinate for the point S .

Consider triangles ASH and ABH :

  1. AS = AB = 1 by condition;
  2. Angle AHS = AHB = 90° since SH is the height and AH ⊥ HB as the diagonals of a square;
  3. Side AH - common.

Therefore right triangles ASH and ABH equal one leg and one hypotenuse. So SH = BH = 0.5 BD . But BD is the diagonal of a square with side 1. Therefore, we have:

Total coordinates of point S:

In conclusion, we write down the coordinates of all the vertices of a regular rectangular pyramid:


What to do when the ribs are different

But what if the side edges of the pyramid are not equal to the edges of the base? In this case, consider triangle AHS:


Triangle AHS- rectangular, and the hypotenuse AS is also a side edge of the original pyramid SABCD . The leg AH is easily considered: AH = 0.5 AC. Find the remaining leg SH according to the Pythagorean theorem. This will be the z coordinate for point S.

Task. Given a regular quadrangular pyramid SABCD , at the base of which lies a square with side 1. Side edge BS = 3. Find the coordinates of the point S .

We already know the x and y coordinates of this point: x = y = 0.5. This follows from two facts:

  1. The projection of the point S onto the OXY plane is the point H;
  2. At the same time, the point H is the center of the square ABCD, all sides of which are equal to 1.

It remains to find the coordinate of the point S. Consider triangle AHS. It is rectangular, with the hypotenuse AS = BS = 3, the leg AH is half the diagonal. For further calculations, we need its length:

Pythagorean theorem for triangle AHS : AH 2 + SH 2 = AS 2 . We have:

So, the coordinates of the point S:

When a person hears the word "pyramid", he immediately recalls the majestic Egyptian structures. However, the ancient stone giants are only one of the representatives of the pyramid class. In this article, we consider from a geometric point of view the properties of a regular quadrangular pyramid.

What is a pyramid in general?

In geometry, it is understood as a three-dimensional figure, which can be obtained by connecting all the vertices of a flat polygon with one single point lying in a different plane than this polygon. The figure below shows 4 figures that satisfy this definition.

We see that the first figure has a triangular base, the second - a quadrangular one. The last two are represented by a five- and hexagonal base. However, the side surface of all pyramids is formed by triangles. Their number is exactly equal to the number of sides or vertices of the polygon at the base.

A special type of pyramids, which differ from other representatives of the class in perfect symmetry, are regular pyramids. For the figure to be correct, the following two prerequisites must be met:

  • the base must be a regular polygon;
  • the lateral surface of the figure should consist of equal isosceles triangles.

Note that the second mandatory condition can be replaced by another one: the perpendicular drawn to the base from the top of the pyramid (the point of intersection of the side triangles) must intersect this base in its geometric center.

Now let's move on to the topic of the article and consider what properties of a regular quadrangular pyramid characterize it. First, let's show in the figure what this figure looks like.

Its base is a square. The sides represent 4 identical isosceles triangles (they can also be equilateral with a certain ratio of the length of the side of the square and the height of the figure). The height lowered from the top of the pyramid will intersect the square in its center (the point of intersection of the diagonals).

This pyramid has 5 faces (a square and four triangles), 5 vertices (four of them belong to the base) and 8 edges. of the fourth order, passing through the height of the pyramid, translates it into itself by rotating 90 o .

The Egyptian pyramids at Giza are regular quadrangular.

Four basic linear parameters

Let's begin the consideration of the mathematical properties of a regular quadrangular pyramid with the formulas for height, length of the side of the base, side edge and apothem. Let's say right away that all these quantities are related to each other, so it is enough to know only two of them in order to unambiguously calculate the remaining two.

Suppose that the height h of the pyramid and the length a of the side of the square base are known, then the side edge b will be equal to:

b = √(a 2 / 2 + h 2)

Now we give the formula for the length a b of the apothem (the height of the triangle, lowered to the side of the base):

a b = √(a 2 / 4 + h 2)

Obviously, the side edge b is always greater than the apothem a b .

Both expressions can be used to determine all four linear characteristics if the other two parameters are known, for example a b and h.

Area and volume of a figure

These are two more important properties of a regular quadrangular pyramid. The base of the figure has the following area:

Every student knows this formula. The area of ​​the lateral surface, which is formed by four identical triangles, can be determined through the apothem a b of the pyramid as follows:

If a b is unknown, then it can be determined by the formulas from the previous paragraph through the height h or the edge b.

The total surface area of ​​the figure under consideration is the sum of the areas S o and S b:

S = S o + S b = a 2 + 2 × a × a b = a (a + 2 × a b)

The calculated area of ​​all the faces of the pyramid is shown in the figure below as its sweep.

The description of the properties of a regular quadrangular pyramid will not be complete if you do not consider the formula for determining its volume. This value for the considered pyramid is calculated as follows:

That is, V is equal to the third part of the product of the figure's height and the area of ​​\u200b\u200bits base.

Properties of a regular truncated quadrangular pyramid

You can get this figure from the original pyramid. To do this, it is necessary to cut off the upper part of the pyramid with a plane. The figure remaining under the cut plane will be called a truncated pyramid.

It is most convenient to study the characteristics of a truncated pyramid if its bases are parallel to each other. In this case, the bottom and top bases will be similar polygons. Since the base in a quadrangular regular pyramid is a square, the section formed during the cut will also be a square, but of a smaller size.

The lateral surface of the truncated figure is formed not by triangles, but by isosceles trapezoids.

One of the important properties of this pyramid is its volume, which is calculated by the formula:

V = 1/3 × h × (S o1 + S o2 + √(S o1 × S o2))

Here h is the distance between the bases of the figure, S o1, S o2 are the areas of the lower and upper bases.



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